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How will the magnetic field intensity at the centre of a circular coil carrying current change,if...

How will the magnetic field intensity at the centre of a circular coil carrying current change,if the current through the coil is doubled and the radius of the coil is halved ?
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Answer #2

Magnetic field intensity is directly proportional to the current. Therefore, if the current is

doubled, the magnetic field intensity will also be doubled. The field intensity is inversely

proportional to radius. Therefore, it will be twice when radius is halved. so it will be four times

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Answer #3

Four times


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B is directly proportional to current

and Inversely proportional to radius

Therefore when current is doubled B becomes double and radius is halved, B becomes double

Total four times

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Answer #4

Magnetic field intensity is directly proportional to the current. Therefore, if the current is

doubled, the magnetic field intensity will also be doubled. The field intensity is inversely

proportional to radius. Therefore, it will be twice when radius is halved.


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Answer #6

M1=M2

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Answer #7

we know from the relation

B = (u_o x N x I/2pi x r)

when the current is doubled and the radius is halved then we have

B1 = (u_o x N x 2I/2pi x (r/2)) = (4u_o x N x I/2pi x r) = 4B

therefore the magnetic field inetnsity increases by four times the original value

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