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The principal strains are given as εp1 = 620 με and εp2 = -490 με, and...

The principal strains are given as εp1 = 620 με and εp2 = -490 με, and the angle of rotation from the x-y coordinate system to the principal-stress coordinate system is θp = -20° for a point in a body subjected to plane strain. Assume εx > εy. Use Mohr’s circle to determine the normal strain εx.

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Solution! Ep1 = 620 ME Ep2 = - 490 ME Op =- 20° X 6 720p A E EP2 0 Eps Y from Mohrs Circle, Ep1 = 0A = 620 ME EP2 - 0B = - 4Co-ordinate of Centre = 0 (66,0) Now, normal strain Ex= OD from A COX, /Dex=20p = 40° CX = R=555 CD= cx Cos 40° = RC0B40° = 5l

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