If you have a concentrated aqueous solution of NaOH that is 12.3% by mass and a...

Question

Question

If you have a concentrated aqueous solution of NaOH that is 12.3% by mass and a density of 1.52 g/ml, what is the molarity?

Answer 1

Answer #1

Let's take 100 g of aqueous solution. In which 12.3 g will be NaOH and 87.7 g will be water.

Molar mass of NaOH = 40g

So, no of moles of NaOH = 12.3/40 =0.30 moles

Volume of solution = volume of NaOH + Volume of water

= ( Mass of NAOH / Density of NaOH ) + ( Mass of water / Density of water )

= (12.3g / 1.52 g/ml ) + ( 87.7g / 1 g/ml )

= 94.79 ml

Molarity = ( no. Of moles of NaOH ) / Volume of solution in litre

= 0.3 mole / ( 94.79/ 1000) litre

= 3.16 M

Answer 2

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