Question

ETI ati Oallow Ti Titanium alloy DTi Aluminum alloy DAL OLAI Oallow AI

Answer 1

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Solution hiven Deuta S=0.025 in, Lri = 16 in , Lai = 13in Ti = Dal = 8in, Eri= 17,400 Ksi (Jau) i = 80ksi Eni = 10,000ksi (Tallal = 3oksi Xri= 5.24000l of Xal = 131 181068oF Let OT be the temperaturi vise to close the gap s In crease in tength of titermium vad + Aluminum yod = 0·025in W. KT Inesease in lengm|sl = 25T] for Ti and Al;- ILTIXTAT I LAILA AT) = 0.02 AT( 1685.2x10 + 13 X 13-18100) = 0.02

AT = 78.8955 °F) Further, system ner, System get heated up and Change in emperature is (AT) from that moment the rod have contact with each of in Induced tact with each other. to rise in temperature the stren Both the pods are compresside stresser Ti rod Allowable stress in Aluminium Rod = stress due to Constraint to Elongation + strey due to force sovested by TAN = 30 = EALA (8T, + Eti X, OT 30 Dtc EALA TEX+; 30 ATC= (10000 X 13, 1X166) +417400X512X105) AT = 135.452°F

To Induce allowable the stress in Al God equal to Temperature rise to be the total (AT, AT TAT-i) Stress = 80ksi - To Induce the allowable in Ti rod, the Total temperature rise is as follow; (AT), = 80 ( 10000 x 130X169) + (17400X5.2X155) ATC = 361-206°F Hence, putting values in eanis to find the total vise Including the gap; (AT, = 3610206 + 78.8955 (OT), = 440.102°F