Question

Suppose Compton used photons of wavelength 0.0384 nm.

(a) What is the energy of one of those photons?
keV

(b) What is the wavelength of the photons scattered in the direction opposite to the direction of the incident photons?
nm

(c) What is the energy of the photon scattered in that direction?

Answer 1

a) The energy of incident photons is hc_1242 eV nm - 32 34 keV 0.0384 nm b) According to Compton effect, the wavelength of scattered photon is 1-cos e) (0.0384 nm)+(24x10-3 nm)(1-cos 10)00432 nm nm )|1- cos180 0.0432 nm cos θ Pac c) The energy of scattered photon is he 1242 eV nm 28.75 ke ' 0.0432 nm