Question

suppose an experiment is done with criminals released from prison in a certain state where the recidivism is the rate is 37%...

App automatically. Up Homework: Homework 8 Save Score: 0 of 1 pt 8 of 35 (5 complete) HW Score: 14.29%, 5 of 35 pts YL 8.1.15 Question Help My Suppose an experiment is done with criminals released from prison in a certain state where the recidivism rate is 37%, that is, 37% of criminals return to prison within three years. One hundred random prisoners are made to attend a "boot camp" for two weeks before their release, and it is hoped that "boot camp will have a good effect. Suppose 33 of those prisoners return to prison within three years. The null hypothesis is that those attending boot camp have a recidivism rate of 37%, p = 0.37 Cou Complete parts (a) through (c) below. Ass a. What is P the sample proportion of successes? (it is somewhat odd to call returning to prison a success.) Stu = 33 (Type an integer or a decimal. Do not round.) b. What is Po, the hypothetical proportion of success under the null hypothesis? Gra n2 Po - 37 (Type an integer or a decimal. Do not round.) n 2 Stal c. What is the value of the test statistic? Explain in context. n 2 Cha (Round to two decimal places as needed.) n3 n Z ете Тоо Mul Pur Dise Enter your answer in the answer box and then click Check Answer Cou 1 part Clear All remaining Check Answer 19 dtv

Answer 1

Answer a:

P value of the sample success = 33/100 =0.33

P vlaue of the null hypohtesis, success of the population = 37% = 0.37

Z = sample mean -standard mean / population standard erro

Poputation standard error = p*(1-p) = (0.37) (0.63) = 0.2331

Z = 0.33 -0.37/0.2331

Z = 0.04 / 0.2331

Z =0.1716

So Z value is 0.17