Question

Solve number Q7

5- Consider the floor plan shown in the Figure 1, Compute the tributary areas for (a) floor beam BI, (b) girder G1, (c) girder G2, (d) comer column C3, and (e) interior column B2. Gi G2 12-24 B2 Bl 12'= 24' C3 Figure 1 Refer to Figure 1, for the floor plan. Calculate the influence areas for (a) floor beam Bl, (b) girder G1, (c) girder G2, (d) cormer column C3, and (e) interior column B2. (Influence AreaKLAT) 6- The uniformly distributed live load on the floor plan in Figure l is 60 lb/ft2. Establish the loading for members (a) floor beam Bl. (b) girder Gl, and (c) girder G2. Consider the live load reduction if permitted by the ASCE standard. 7-

Answer 1

Floor beam B1: Tributary area A_T = span times width Tributary Area,A_T = 35[12/2 + 12/2] 420ft^2 live load reduction factor in 2 k_llA_T = 2 times 420 = 840ft^2 840ft^2 > 400 L = L_0[0.25 + 15/ squareroot K_LLA_T] L = 552.6lb/ft Girder G_1 Tributary Area A_T = span times width Tributary Area A_T = 35/2 times [12/2 + 12/2] L = 58.91 times 12 L = 706.99lb/ft^2 Compute the reaction from beam B1: R = w1/2 R = 12419.05lb load to girder G1 from B1 Girder G_2 A_T = 12 times [35/2 + 30/2] A_T = 390ft^2 K_LL = 780ft^2 L = 47.225lb/ft^2 R = W1/2 R = 991.729lb R = W1/2 R = 8500.5lb Load on grider G_2 = 8500.5 + 9917.29 load on grider G_= 18417.79lb Therefore, the girder G2 in 18417.79lb