Question

B) 2.61 to 5.41 iters D)3.92 to 4.11 Iitej A) 3.65 fo 4.37 liters C) 59.84 to 60.56 liters 3) Find the z-score corresponding to the given value and use the z-score to determine whether the value is unusual. Consider a score to be unusual if it is at least three standard deviations above or below the mean. test score of 90.6 on a test having a mean of 73 and a standard deviation of 11. B) 1.6; unusual D) 17.6; unusual A) 1.6, not unusual C) -1.6; not unusual

Answer 1

Date: 01/11/2019 Answer The z-score for the test score of 90.60 is, x- 90.60 73 11 = 1.60 The z-score for the test score of 90.60 is 1.60 The value of z-score is not unusual due to z-score fall within three standard deviation of the mean which is 1.60 The answer is A