Question

20. This problem should be done without any phasor voltage or current computations. In the circuit of Figure P11.20, V = 2300

Clear and concise handwriting please with explanation. Thank you.

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roblem Comples Po delvered by orce - 20+j8 204j(8+ S+j6 3+j4 =(483) kVA (8+36) = 20 82+jI5.652 2300 - 20 8-jI5.52A 26.os-36.8Comples oscr delvered 2.2 2 gaoop ofinfedonses 2D& 20+j18 +3+ jy (3 0k ( ltaye duisin rale) V, = V, x_2a 23t sztSa 2300 x (43(27 200. 8L96) X (20+513) K (2t9yt(20+)K 22 22+24 - (1695. 58 -jioq.R)V. -V.x 2 2(22+2 = , + x S2 D

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