Find Sla 4x – 4y 52 + y dA, where R is the parallelogram enclosed by...

Question

Question

Answer 1

Answer #1

5 SOlution: 4x-4y LA parallelogram with lines: 5x+y 4x - 4y= 0 4x - 4y= 9 5x+y=1 5x+y=5 Letu = 4x - 4y and v=5x+y >0<u<9 and

Answer 2

Similar Homework Help Questions

Find integral integral _ 4x + 3y/2x - 3y dA, where R is the parallelogram enclosed...

Find integral integral _ 4x + 3y/2x - 3y dA, where R is the parallelogram enclosed by the lines -4x + 3y = 0, - 4x + 3y = 6, 2x - 3y = 1, 2x - 3y = 4 This can be done directly with a tedious computation, or can be done with a change of variables to transform the parallelogram into a rectangle.
2x-y Findle-4-, where R is the parallelogram enclosed by the lines dA, This can be done directly with a tedious computation, or can be done with a change of variables to transform the parallelogram i...

2x-y Findle-4-, where R is the parallelogram enclosed by the lines dA, This can be done directly with a tedious computation, or can be done with a change of variables to transform the parallelogram into a rectangle. HINT: Let u 2z -y and v-4 - 2y -27/16 *Preview and y - 2x-y Findle-4-, where R is the parallelogram enclosed by the lines dA, This can be done directly with a tedious computation, or can be done with a change of...
Evaluate the given integral by making an appropriate change of variables dA, where R is the...

Evaluate the given integral by making an appropriate change of variables dA, where R is the parallelogram enclosed by the lines x-7y-0, x-7y-9, 4x-y 6, and 4x-y= 7 R4x -y Need Help? Read ItWatch ItMaster ItTalk to a Tutor

Evaluate the given integral by changing to polar coordinates. ∫∫R(4x − y) dA

Evaluate the given integral by changing to polar coordinates. ∫∫R(4x − y) dA, where R is the region in the first quadrant enclosed by the circle x2 + y2 = 4 and the lines x = 0 and y = x.
Calculus 4 class please help ASAP Due in 1 hour If R is the parallelogram enclosed...

Calculus 4 class please help ASAP Due in 1 hour If R is the parallelogram enclosed by these lines: - 2x + 6y = 0, - 2x + 6y = 2, x – 5y = 1 and X – 5y = 7,/div> then: STA 2x + 6y dA x — 5y R
8 0/1 points | Previous Answers SEssCalcET2 12.8.024 !My N Evaluate the integral by making an appropriate change of variables where R is the rectangle enclosed by the lines x -y-o, x -y-3, x+y o, and...

8 0/1 points | Previous Answers SEssCalcET2 12.8.024 !My N Evaluate the integral by making an appropriate change of variables where R is the rectangle enclosed by the lines x -y-o, x -y-3, x+y o, and x y - s 9(x + y)e- y* dA, 8 0/1 points | Previous Answers SEssCalcET2 12.8.024 !My N Evaluate the integral by making an appropriate change of variables where R is the rectangle enclosed by the lines x -y-o, x -y-3, x+y o,...

Evaluate: vr y-x dA , y + 2x+1 where R is the parallelogram bounded by y-x-2, y-x-3, y + 2x = 0, andy+2x=4. Evalua...

Evaluate: vr y-x dA , y + 2x+1 where R is the parallelogram bounded by y-x-2, y-x-3, y + 2x = 0, andy+2x=4. Evaluate: vr y-x dA , y + 2x+1 where R is the parallelogram bounded by y-x-2, y-x-3, y + 2x = 0, andy+2x=4.
• SSS, y dv, where E is the solid bounded by the parabolic cylinder z =...

• SSS, y dv, where E is the solid bounded by the parabolic cylinder z = z? and the planes y = 0 and Find z = 10 - 4y Round your answer to four decimal places. Preview Get help: Video Video Li- Points possible: 1 This is attempt 1 of 3.
Compute the Riemann sum S for the double integral Sla (3x - 6) dA where R...

Compute the Riemann sum S for the double integral Sla (3x - 6) dA where R = [1,4] [1, 3), for the grid and sample points shown in figure below. S 3 2 . 1 1 2 3 4 Match the functions below with their graphs (A)-(F). (A) (B) (D) (E) (F) (a) f(x,y) - 1x1 + ly! OA B O

4. Co ider dĀ, where R is the parallelogram enclosed by the lines x-3y=0, x-3y=4, 2x-y=2,...

4. Co ider dĀ, where R is the parallelogram enclosed by the lines x-3y=0, x-3y=4, 2x-y=2, Å 2x - y and 2x-y=7. Fill in the boxes: Let u=x-3y, and v= 2x - y. Then in terms of u and v, we can set up the PX - 3 ingen i 19 = 3/d2=SHH dvdu. (You do not actually evaluate the integral.) dvdu van de integral as: JJ 2 actually salane te imeni)