Evaluate the given integral by changing to polar coordinates. ∫∫R(4x − y) dA, where R is the region in the first quadrant enclosed by the circle x2 + y2 = 4 and the lines x = 0 and y = x.
Evaluate the given integral by changing to polar coordinates. ∫∫R(4x − y) dA
3. Evaluate the integral by changing to polar coordinates: SS (x+y) da R Where R is the region in quadrant 2 above the line y=-x and inside the circle x2 + y2 = 2.
7. Evaluate the following integral by converting to polar coordinates: S], 127 (2x – y)dA, where R is the region in the first quadrant enclosed by the circle x2 + y2 = 4 and the lines x = 0 and y = x. 8. Find the surface area of the portion of the plane 3x + 2y +z = 6 that lies in the first octant. 9. Use Lagrange multipliers to maximize and minimize f(x, y) = 3x + y...
1. Use polar coordinates to evaluate the double integral dA z2 +y where R is the region in the first quadrant bounded by the graphs x = 0, y = 1, y=4, and y V3z. 1. Use polar coordinates to evaluate the double integral dA z2 +y where R is the region in the first quadrant bounded by the graphs x = 0, y = 1, y=4, and y V3z.
Use polar coordinates to evaluate the integral where R is the region in in the first quadrant enclosed by the circumference x2+y2=4 and the lines x=0 and y=x SUR (60 - 3y)dA Use coordenadas polares para evaluar la integral JR (6x – 3y)dA donde R es la región en en el primer cuadrante encerrada por la circunferencia za + y2 = 4y las rectas r = Oyy=2. 0-8+12V2 O NO ESTÁ LA RESPUESTA O 16 - 12/2 O 12 -...
Can you please solve both of these problems? Evaluate the given integral by changing to polar coordinates. 9(x + y) dA where R is the region that lies to the left of the y-axis between the circles x2 + y2 = 1 and x2 + y2 = 4. , -378 Need Help? Read It Master It Talk to a Tutor -11 points v SCALCET8 15.3.511.XP. Evaluate the given integral by changing to polar coordinates. Il V25 – x2 + y2...
3. Draw the region D and evaluate the double integral using polar coordinates. dA, D= {(x, y)| x2 + y² <1, x +y > 1} (b) sin(x2 + y2)dA, D is in the third quadrant enclosed by D r? + y2 = 7, x² + y2 = 24, y = 1, y = V3r.
Q4: Use polar coordinates to evaluate x2 - y2 dA, where R is the region in the first V9- quadrant within the circle x2 + y2-9.
10. Evaluate the given integral by changing to polar coordinates. JJR x2 + y2" where R is the region that lies between the circles x2 + y2 = a2 and x2 + y2 = 62 with 0 <a<b.
3. Draw the region D and evaluate the double integral using polar coordinates. (a) SI x + y dA, x2 + y2 D= {(x, y)| x2 + y2 < 1, x + y > 1} D (b) ſ sin(x2 + y2)dA, D is in the third quadrant enclosed by m2 + y2 = 71, x2 + y2 = 27, y=x, y= V3x.
Please do #2 40 1. 16 pts) Evaluate the integral( quadrant enclosed by the cirle x + y2-9 and the lines y - 0 and y (3x-)dA by changing to polar coordinates, where R is the region in the first 3x. Sketch the region. 2. [6 pts) Find the volume below the cone z = 3、x2 + y2 and above the disk r-3 cos θ. your first attempt you might get zero. Think about why and then tweak your integral....