From the given enthalpies of formation, calculate the enthalpy change for the following reaction. Your label...
help asap 3. Calculate the standard enthalpy change, Hº, for the following reaction using standard enthalpies of formation. (1 point) 2C2H2(g) + 502(g) → 4CO2(g) + 2H20(1) Standard Enthalpies of Formation AH for C2H2(g) = +226.7 kJ/mol AHfor CO2(g) = -393.5 kJ/mol AH for H2O(l) = -285.8 kJ/mol
calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l) Given the reactions N2H4(l) + O2(g) -> N2(g) + 2H2O(l) Enthalpy of H = -6.22.2 kJ H2(g) + (1/2)O2(g) -> H2O(l) enthalpy of H = -285.8 kJ/mol H2(g) + O2(g) -> H2O2(l) enthalpy of H = -187.8 kJ
72. Determine AHº for this reaction from the data below. N2H4(1) + 2 H2O2(1) -→ N2(g) + 4H2O(1) N2H4(1) + O2(g) →→ N2(g) + 2 H2O(1) A Hº = -622.2 kJ mol-1 H2(g) + + O2(g) →→ H2O(1) A Hº = -285.8 kJ mol-1 H2(g) + O2(g) —> H2O2(1) A,Hº = -187.8 kJ mol-1
A.Using standard heats of formation, calculate the standard enthalpy change for the following reaction. N2(g) + 3H2(g) = 2NH3(g) B.Using standard heats of formation, calculate the standard enthalpy change for the following reaction. CaCO3(s) = CaO(s) + CO2(g) C. A scientist measures the standard enthalpy change for the following reaction to be -2910.6 kJ: 2C2H6(g) + 7 O2(g) = 4CO2(g) + 6 H2O(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy...
19. What is the standard enthalpy of formation of liquid butyraldehyde, CH:CH2CH2CHOCO CHỊCH CHỊCHOI) + 30g) – 4H2O) + 4CO(g); AH = -2471.8 kJ Substance AH/(kJ/mol) CO2(g) -393.5 H2O(1) -285.8 a. -245.4 kJ/mol b. +245.4 kJ/mol c. -1792.5 kJ/mol d.-3151.1 kJ/mol e. +3151.1 kJ/mol
Calculate the enthalpy change for the following reaction: N2H4 (I)+ 2 H2O2 (I) → N2 (g) + 4 H2O (I); ΔH=? kJ Using the following thermochemical equations:
19. What is the standard enthalpy of formation of liquid butyraldehyde, CH:CH2CH2CHOCO CHỊCH CHỊCHOI) + O2(g) – 4H2O) + 4CO(g); AH = -2471.8 kJ Substance AH/(kJ/mol) CO2(g) -393.5 H2O(1) -285.8 a. -245.4 kJ/mol b. +245.4 kJ/mol c. -1792.5 kJ/mol d. -3151.1 kJ/mol e. +3151.1 kJ/mol
4. Calculate the energy change for the following reaction, using the standard enthalpies of formation provided. SO2Cl2 (I)+2 H2O (I)2 HCI (g) + H,SO4 ) Substance AH (/mol) SO-ClO H2O0) HO(g) НСКО НС 9) H2SO 0) H-SO (aq) -394.1 -285.8 -241.8 92.3 -167.2 814.0 -909.3 If 25.0 kJ of heat energy is added to 50.0 g of water initially at 25°C, what will be the final temperature of the water? The specific heat of water is 4.18 J g1 °C
answer should be in sig figs. LReterences] TUTOR Calculating Enthalpy Change Using the standard formation enthalpies that follow, calculate the standard enthalpy change for this reaction. 2CO(g)+2NO(g)2CO2(g)+ N2(g) AH kJ Species AHo (kJ/mol) -110.5 CO(g) NO(g) CO2(g) 90.3 -393.5
Calculate the AH formation of octane, CBH1B (), given that the enthalpy of combustion of octane is -5471 kl/mol and the standard enthalpies of formation of H20 () and CO2 (g) are -393.5 kJ/mol and -285.8 kJ/mol respectively.