19. What is the standard enthalpy of formation of liquid butyraldehyde, CH:CH2CH2CHOCO CHỊCH CHỊCHOI) + O2(g)...

Question

Question

Answer 1

Answer #1

Given:

ΔHo rxn = -2471.8 KJ/mol

Hof(O2(g)) = 0.0 KJ/mol

Hof(H2O(l)) = -285.8 KJ/mol

Hof(CO2(g)) = -393.5 KJ/mol

Balanced chemical equation is:

CH3CH2CH2CHO(l) + 5/2 O2(g) ---> 4 H2O(l) + 4 CO2(g)

ΔHo rxn = 4*Hof(H2O(l)) + 4*Hof(CO2(g)) - 1*Hof( CH3CH2CH2CHO(l)) - 5/2*Hof(O2(g))

-2471.8 = 4*(-285.8) + 4*(-393.5) - 1*Hof(CH3CH2CH2CHO(l)) - 5/2*(0.0)

Hof(CH3CH2CH2CHO(l)) = -245.4 KJ/mol

Answer: a

Answer 2

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