At 425 K, this reaction has a Kc value of
0.0116.
2X (g)+2Y (g) **arrows left and right** 2Z (g)
calculate Kp at 425 K.
Kp=?
use the following expression: Kp = Kc(RT)dn
dn is the difference of the coefficients of the products and
reactants, which in this case:
dn = (2) - (2+2) = -2
Using R = 0.0821 L atm/mol K and T = 425 K let's calculate Kp:
Kp = 0.0116 / (0.0821*425)2
Kp = 9.53x10-6
Hope this helps
At 425 K, this reaction has a Kc value of 0.0116. 2X (g)+2Y (g) **arrows left...
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22 A) For the reaction
2A(g)+3B(g)⇌C(g)
Kc = 40.0 at a temperature of 165 ∘C∘
Calculate the value of Kp
22 B) For the reaction
X(g)+2Y(g)⇌2Z(g)
Kp= 1.87×10−2 at a temperature of 67 ∘C
Calculate the value of Kc
Part A For the reaction 2A(g) + 3B(g) = C(g) Kc = 40.0 at a temperature of 165 °C. Calculate the value of Kp. Express your answer numerically. View Available Hint(s) | ΑΣφ ? Submit Part B For the reaction X(g)...
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