Question

h t , Kfor the followme 0.116 33 121 L C 0.271 ,600.00 MNH, 0212 MHS What the b e the 11,5- most

Answer 1

WHY Hg (S) = NH3(g) + Hys(9) concentration - molis in Volumi. the scend case, mole will remain. miely volume wake chang. so concentration of EN NHz in first step BU a46o.it helul volume - 121 L Vin Volum 645L 0.460 = molu. 21 22 moles = 5.56. . 5.56 6-45 0.86. mol/LerM Now in Acond was the CNM, ) = molis Vouny concentration of H₂s in first stef = 0.272. So 0.272 = moles 121. moles - 3.29 Now in biond do the CHS) = miles Volume 3.29 645 . 0.51 mol/la M to Inn] =0.86M [HS] = 0.51 M