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Given the differential equation y"' + 5y' – 4y = 4 sin(3t), y(0) = 2, y'(0)...
Given the differential equation y” + 5y' – 4y = 4 sin(3t), y(0) = 2, y'(0) = -1 Apply the Laplace Transform and solve for Y(s) = L{y} Y(s) = (293 +52 + 188 +21) (52 +58 - 4)( 92 +9)
Question 5 < > Given the differential equation y' + 5y' + 4y = 0, y(0) = 2, y'(0) = 1 Apply the Laplace Transform and solve for Y(8) = L{y} Y(s) = Now solve the IVP by using the inverse Laplace Transform y(t) = L-'{Y(s)} g(t) =
Given the differential equation y" – 4y' + 3y = - 2 sin(2t), y(0) = -1, y'(0) = 2 Apply the Laplace Transform and solve for Y(8) = L{y} Y(S) -
please solve with steps and explain thanks Question 5 Given the differential equation y'' + 5y' + 4y = 0, y(0) = 2, y'(0) = 1 Apply the Laplace Transform and solve for Y(8) = L{y} Y(8) = Now solve the IVP by using the inverse Laplace Transform y(t) = L-'{Y(s)} g(t) =
Given the differential equation y"' + 3y' - y = 5 sin(2t), y(0) = 1, y'(0) = 0 Apply the Laplace Transform and solve for Y(s) = L{y} Y(3) -
Given the differential equation y' + 367 - ezt, y(0) = 0, y'(0) = 0 Apply the Laplace Transform and solve for Y(s) = L{y} Y(s) = Now solve the IVP by using the inverse Laplace Transform y(t) = L-1{Y(s)} g(t) =
Given the differential equation y'' – 9y = - ett + 3e8t, y(0) = 0, y'(0) = 4 Apply the Laplace Transform and solve for Y(8) = L{y} Y(s) = Preview Now solve the IVP by using the inverse Laplace Transform y(t) = L '{Y(8)} g(t) = Preview
Find the general solution of the given non-homogenous differential equation. Show each step of your work: y"+5y+4y=10e^(-3t)
(1 point) Consider the initial value problem 4y 8t, y(0) 4, y'(0) 3. f both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from othe other (until you get to part (b) below). Take the Laplace transform one side of the equation help (formulas) b. Solve your equation for Y(8) Y(s) C{y(t) = Take the inverse Laplace transform of both sides of the...
(1 point) Transform the differential equation -87 5y" +42y" - 5y' - 42y = 2e y(0) = 0 VO) = 0 y"(0) = 1 into an algebraic equation by taking the Laplace transform of each side. Use Y for the Laplace transform of y, (not Y(s)) Therefore 1+ 3+1 *+8 Taking the inverse Laplace transform we get y