Question

(a) A piston at 6.8 at contains a gas that occupies a volume of 3.5 L What pressure would have to be placed on the piston to force the volume to adjust to 1.6L? (D) A piston at 77.0°C contains a gas that occupies a volume of 2.5 L To what temperature would the gas have to be heated to increase the volume to 5.9 Lat constant pressure? (c) A piston at 6745 torr contains a gas that occupies a volume of 4.7 L. What pressure would have to be placed on the piston to force the volume to adjust to 0.99 L atm

Answer 1

Vlag A Piston at 6.8 atm contains a gas that occupiel a raume of 3.5L u by changing the pressure of Preton the volume of gas becomes 1.sh. Here the member of moles gas and temperature are constant in the process from initial state to binal state, Hence we can apply Boyles la which states that temperature, remaining Constant, Volume of a given mass of gas. is inversty pooperational to pressure. ie pat si and T are constant. n=moles T-temperature Pivi = P₂ 2 1 Here Pianital pressure) 6.8 atm V (initial volume ) = 3.5L. B = final pressure in atm = 2 - Final volume 1.5L Now PV = P₂ kg P2 = Pivo = 6.80 3.5 Va 105 15.87 atm. Hence the final pressure of gas = 15.87 atm. (6) A piston at 17.00 Contains a gas that occupies a volume of 2.5L .. By changing temperature, the volume increases to s i at Constant pressure,

rocess he Here pressure Constant and moles of gas constant during the pro Hence it states e it obey chaffer law, which obey charted! That pressure remaining Constant, Yolume of a ginen mass of gas is directly proportional to Volume Hence ve T (P. and & constant) V moles e = constant Po pressure, > y = 12 То Here V = initial Yolume = 2.5 L Ti= initial temperature= 77c = 77+273 = 350k V2 = Final Volume = 5.9L - 350k T2=final temperature=? – V/₂ TL - 5.98 350_896k Hence I - T2 - 1 V 2.5 Hence temperature of the gas = 826k) -826-273 = 5530 (c) Here initial pressure P 6745 toor initial volume 4.72 T= constant in final volume - 0.99L Mass = constant Final pressure (P2) = ? this conclition a 180 obey Boylets law. Hence Piv=P = P2= Bu B = 6745tors x 4.7L - 32022 toor V2 Hence Pa pressure in atm = 32022 = 42.15 atm Hence final 760 pressure s 42.13 atan? 0.99L