Question

6. A handball, of mass 0.10 kg, traveling horizontally at 25 m/s, strikes a wall and rebounds at 19 m/s. What is the change in the momentum of the ball? A) 0.60 N-s B) 72 N-s C) 1.2 N-s D) 1.8 N-s E)4.4 N-s
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Answer #1

Let us assume the initial velocity direction of the handball as negative.

Mass of the handball = m = 0.1 kg

Initial velocity of the handball = V1 = -25 m/s

Velocity of the handball after rebounding from the wall = V2 = 19 m/s

Change in momentum of the ball = \Delta P

\Delta P = mV_{2} - mV_{1}

\Delta P = (0.1)(19) - (0.1)(-25)

\Delta P = 4.4 N.s

Change in momentum of the handball = 4.4 N.s

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