A 28.0kg child plays on a swing having support ropes that are 2.10m long. A friend pulls her back until the ropes are 43.0%u2218 from the vertical and releases her from rest.
part a
What is the potential energy for the child just as she is released, compared with the potential energy at the bottom of the swing?
part b
How fast will she be moving at the bottom of the swing?
part c
How much work does the tension in the ropes do as the child swings from the initial position to the bottom?
1)H =L (1-cos(theta)) = 2.1(1-cos(43)) = 0.564
2)Taking PEat bottom = 0
Potential energy(PE) = mgH = 28*9.8*0.564 = 154.76 J
3) From conserevation of energy principle
(PE + KE)initial = (PE+KE)bottom
KE ntial = 0 becuase no velocity. the child is hold
there
154.76 = KE bottom
1/2*m*V2 = 154.76
V = 3.33 m/s
4) W = T.dr
( dot product of T and dr)
dr is the tanzential direction
dr is perpendicuar to T
W = 0
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