Question

You might get partial grades from this question. Solve this problem on paper, then, in 5 minutes after you finish your exam, take its photo with your ID on it and e-mail to the instructor motor flexible cables elevator Vo=1 m/s E The elevator in the figure is suspended by four flexible steel cables of diameter d=13 mm and modulus of elasticity E = 200 GPa. While it is going down with a speed of Vo = co = 1 m/s, it suddenly stops when cable length is L= 11 m, causing the cabin to vibrate. The mass of the cabin is m = 1297 kg. Neglect damping and static deflection of cables (S = 0,30 = 0). What is the maximum normal stress in one cable while the cabin is vibrating? Enter below in MPa, without using any digits after the decimal point.

Answer 1

Given, d= 13mm, E = 200 Gpa. Vo=ão = lm/s. L = 11m, m=1297kg, 820, 1=0. x 1297 x 1 648.5 As we know that when the system is moving. The kinetic Energy is given by ke - mot. 늘 This Energy is absorbed by the rope the maximum stress produced in supe. Taking Then, max. Energy can be given by •XAX LX 4 attached) مه (یا 2E (As 4 cables are

Equating it with the ke of the system, 6+8 г*xтx (13) х 11 х + -Х -оохочx+x(looo) 64 85 хъх юол ок4 xio 6 3 Лх 169x 1 x+ 3 103 76 x to ”. 44. 39 85 Ф лх 164x x4 Xlo's эс" ++2. 48 254 хо"* Э аге аlо. ПъR-44 г- а/, о-о-44 х 12 | 2 е. 2 to. - МР) Ф Maximum stress
Maximum Stress without any digit after the decimal can be rounded off to 211 MPa

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