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how do you solve this? At 450°C, tert-butyl alcohol decomposes into water and isobutene. (CH3)3COH(g) =(CH3)2CCH2(g)...
1.At 450°C, tert-butyl alcohol decomposes into water and isobutene. (CH3)3COH(g) (CH3)2CCH2(g) + H2O(g) A reaction vessel contains these compounds at equilibrium. What will happen if the volume of the container is reduced by 50% at constant temperature? A. The forward reaction will proceed in order to reestablish equilibrium. B. The reverse reaction will proceed in order to reestablish equilibrium. C. No change occurs. D. The equilibrium constant will increase. E. The equilibrium constant will decrease. 2. The following reaction is...
1.0 x 100 M 1.3 x 105 4.0 x 1011 M 1.6*10-10 M QUESTION 4 At 450°C, tert-butyl alcohol decomposes into water and isobutene: (CH3)3COH(g) = (CH3)2CCH2(g) + H2O(g) A reaction vessel containing these compounds is at equilibrium. What will happen to the equilibrium If the volume of the container is reduced by 50% at constant temperature? The equilibrium constant will increase. The equilibrium constant will decrease. The reverse reaction will proceed to re-establish equilibrium. The forward reaction will proceed...
art A Multiple choice each question is worth 5 points each for a total of 95 points Here is a reaction: A + 2 .D with the following concentrations: IAI - 2mM. (B) = Smm. (C) - 2mM, ID - 3mM The equilibrium constant for this reaction is 4mm Which direction will this reaction proceed to attain equilibrium? Forward d. It cannot ever attain equilibrium b. Reverse e. There is insufficient information to answer this It's already at equilibrium 2....
student question: 75 mL, of water and 0.10 moles of CO.(g) are added to a on vessel at 25 °C. A) What concentration of CO.(aq) do you expect to find at equilibrium? Henry's law constant-2 4x102 mol/L atm (12 pts) I mal-o B) Modified student question: If all the dissolved Co.(aq) reacts fully with water, then what is the pH of the water after equilibrium is reached? H2CO3 Kal = 4.2x10", Ka2-4.8×10-11. (12 pts) C) If you add CaCl2 to...