Net resistsne on right side = R7 + (R5R6/R5+R6) = 3.4 + (43.5/13.7) = 6.58 ohm
Current i4 = 32.6/4.35 = 7.5 A
Volatge across R7 = i4xR7 = 7.5x3.4 = 25.5V
Voltage across R5 and R6 = 25.5 V
So, current i5 = 25.5 /2 = 12.75 A
Net resistsne on left side = (R1R2/R1+R2) + (R3R4/R3+R4) = 17.35 ohm
so i2 = 30/10 = 3A
i1 = i2+i4 = 17.35 +7.5 = 24.85A
Voltage across R3 and R4 =i2* (R3R4/R3+R4)= 3*3 = 9V
so i3 = 9/R3 = 9/6 = 1.5A
In the figure the ideal battery has emf expectation = 32.6 V, and the resistances are...
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