Solution
a) Latent heat of fusion of ice, Hf= 334 J/g
Energy tried to melt the ice, E= m*Hf= 300*334 J = 100200 J
b) using, Q= m*c*
Let T be the equilibrium temperature.
Hear loss= Heat Gain
200*4.18*(95-T) = 100200 + 300*4.18*(T-0)
T can not be negative
So, T is 0 °C
heat loss by hot water, Qh= 200*4.18*(95-0) = 79800 J
So, ice will not completely melt.
phase present are solid and liquid.
c) Melting point of lead is 327 °C
specific heat of lead, c' = 0.128 J/(g°C)
Latent heat of fusion of lead, H= 23 J/g
Let m be the mass of water needed.
heat loss=heat gain
10*0.128*(480-327) + 10*23 + 10*0.128*(327-99) =m*4.18*(99-0)
or, mass of water required, m= 1.8 g
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