Three 101.0-g ice cubes initially at 0°C are added to 0.820 kg of water initially at 19.5°C in an insulated container. (a) What is the equilibrium temperature of the system? °C (b) What is the mass of unmelted ice, if any, when the system is at equilibrium? kg
Here,
let the equilibrium temperature of the system is T
heat needed to melt ice = 3 * 101 * 334 = 101202 J
heat released when the water reaches 0 degree C = 0.820 * 4186 * (19.5 - 0)
heat released when the water reaches 0 degree C = 66934 J
hence , there is not enough heat to melt the ice
the final temperature will be 0 degree C
part B)
let the unmelted ice is m
heat released = (3 * 101 - m) * 334
66934 = (303 - m) * 334
m = 102.6 gm
the mass of ice remaining is 102.6 gm
Three 101.0-g ice cubes initially at 0°C are added to 0.820 kg of water initially at...
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