Question

please solve it quickly and clearly

2. If A572 Grade 50 steel is used. a. Compute the plastic section modulus Z and the plastic moment Mp with respect to the major principal axis. b. Compute the elastic section modulus S and the yield moment My with respect to the major principal axis. 22 inch 3 inch Thickness of web = 0.5 inch 66 inch 3 inch 16 inch

Answer 1

The solution of the given problem is given below

Solution : briven data : A 572 rade 50 steel minimum Yield Stress (fy) = 50,000 psi n Izin 9 Equal area auf oisis 66 ink Heutral and Lel gin If in ty calculation No A. 22 x3 x * [*+ 66+3] + 66 x0.5 * [* +3] + 1673 * plus 2283 + 66 * oos T 16 4 3 ☺ = 40.22 mm [ N.A.) (from bottom ) calculation of equal areal aris 22 43 0.5 x y = 16.43 + (66-4) fois 66 Osy 48 + 66 *6.5 0.59 y 48 # 33 - 66 y = 15 mm 19

calculation of plastic section modulus - (2) z = Acte At It Ac - 22 x3 x Sc (+15) + Ors A15 * Is Actc 1145.25 in? ALYE 16 3 1 ( + 51) + 0.5 IS A 51 3 ALYE = 4411.25 z = AcYc & ALYE z = 1145.25 +2711.25 3 z = 38 56.5 in * calculation of plastic moment Mp principal with respect to majordanes a Mp = z ty ме 3856.5 # 50000 Mp 1928 25000 prin 192825 kip in Mp b' calculation elastic section modului (S) * I moment of roinertia 0.5g 5863 16- 136-40.22 +0.5 x 66 x 22 * 33 H + 22 3 of (7015-2022 12 12 16733 40122) + 16 x3 (1-5- + - 145129.5948 in - [

1 lust*29. 5948 Sa प 40.22 3 Us 3608.39 in cal culation of yield moment my with with respect to major principal anti- s fy. My му 3608.39 * 50000 My 190419 500 P-in му 18oul9.5 kip-in