Two identical coil springs are mounted side by side so that they jointly support a weight...
Homework Answers
force constant of each spring is k.
so when mounted side by side then keq = 2k
and F = keq x
2 = 2k (x1)
x1 = 1/k
for additional weight,
2 + 4 = 2k(x1 + 0.05)
6 = 2kx1 + 2k(0.05)
6 = 2 + 0.01k
k = 40 N/m
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