Question

A sled of mass 1095 kg is propelled by a rocket. The forceexerted by the...

A sled of mass 1095 kg is propelled by a rocket. The force exerted by the rocket when it is burning is 7.84×103 N. Assume that the force of friction opposing the motion is 1380 N, what is the acceleration of the sled?

1 0
Add a comment Improve this question Transcribed image text
Answer #1

net force = ma

F-f = ma

here F = 7.84*10^10^3 N

f = 1380 N

m = 1095 kg

a = 7840-1380/1095 = 5.89 m/s^2

Add a comment
Know the answer?
Add Answer to:
A sled of mass 1095 kg is propelled by a rocket. The forceexerted by the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 1. Consider the rocket sled below. The mass of the system is 2.1 x 103 k...

    1. Consider the rocket sled below. The mass of the system is 2.1 x 103 k a. If the rocket sled decelerates at 196 m/s', what force is necessary to produce this deceleration? Assume the rockets are off. If the rocket sled starts from rest with only one rocket burning, what is the magnitude of its acceleration? Assume the thrust is T = 2.4 × 104 N and the force of friction opposing the motion is f-650 N With four...

  • The mass of the system of the rocket sled shown in the figure is 2100 kg

    The mass of the system of the rocket sled shown in the figure is 2100 kg, and the force of friction opposing the motion is known to be 625 N. The thrust for the rocket sled is 2.59 x 104N Randomized Variables f=625 N What is its acceleration in m/s2?

  • An 84.0 kg sprinter starts a race with an acceleration of 1.44 m/s2

    1. An 84.0 kg sprinter starts a race with an acceleration of 1.44 m/s2. If the sprinter accelerates at that rate for 41 m, and then maintains that velocity for the remainder of the 100 m dash, what will be his time (in s) for the race? 2. (a) If the rocket sled shown in the figure below starts with only one rocket burning, what is the magnitude of its acceleration (in m/s2)? Assume that the mass of the system is 2090...

  • step by step explanation please 03. An experimental rocket propelled sled runs on a straight horizontal track. A friction force for which 0.10 acts between the sled and the track (a) Working from...

    step by step explanation please 03. An experimental rocket propelled sled runs on a straight horizontal track. A friction force for which 0.10 acts between the sled and the track (a) Working from first principles and neglecting air resistance show that the nstantaneous acceleration a of the sled is given by iu where: h mass burn rate of the propellant eexhaust efflux velocity measured relative to the sled M instantaneous mass of the sled g-acceleration due to gravity 12 marks...

  • Coyote (mc = 16.0 kg) is about to try out his new rocket sled invention (mt = 50.0 kg)

    Coyote (mc = 16.0 kg) is about to try out his new rocket sled invention (mt = 50.0 kg), which can produce a thrust of 1600 N.  Part A: What is the normal force (Fs) exerted upwards by the road?  Part B: If the effective frictional coefficient between the rolling wheels and the road is μ = 0.050 what is the value of the frictional force (f) Part C: What will be the value of the acceleration (a) while Coyote and the apparatus...

  • Coyote (mc = 14.0 kg) is about to try out his new rocket sled invention (mt = 55.0 kg)

    Coyote (mc = 14.0 kg) is about to try out his new rocket sled invention (mt = 55.0 kg), which can produce a thrust of 1700 N.  Part A: What is the normal force (Fs) exerted upwards by the road?  Part B: If the effective frictional coefficient between the rolling wheels and the road is μ = 0.060 what is the value of the frictional force (f) Part C: What will be the value of the acceleration (a) while Coyote and the apparatus are in...

  • Coyote (mc = 14.0 kg) is about to try out his new rocket sled invention (mt = 45.0 kg)

    Coyote (mc = 14.0 kg) is about to try out his new rocket sled invention (mt = 45.0 kg), which can produce a thrust of 1600 N.  Part A: What is the normal force (Fs) exerted upwards by the road?  Part B: If the effective frictional coefficient between the rolling wheels and the road is μ = 0.050 what is the value of the frictional force (f) Part C: What will be the value of the acceleration (a) while Coyote and the apparatus are in...

  • The mass of the child with the sled is 25 kg and the magnitude of the...

    The mass of the child with the sled is 25 kg and the magnitude of the push on the child is 45 N acting to the left. The coefficient of kinetic friction between the sled and the snow, mk = 0.15. The magnitude of the friction force is _____N The net force acting on the child-sled system is _____    What will be the ACCELERATION of the sled shown below? _____ m/s2

  • A father pulls a sled and child with a force of 220 N by a rope...

    A father pulls a sled and child with a force of 220 N by a rope making an angle of 20 degree with the horizontal. If the sled and child has a mass of 47 kg, to the nearest hundredth of 3 m s what is the acceleration of the sled and child? Two crates of mass 75 kg and 110 kg arc in contact and rest on a rough horizontal surface. A 620 N force is exerted on the...

  • A mysterious rocket-propelled object of mass 44.0 kg is initially at rest in the middle of...

    A mysterious rocket-propelled object of mass 44.0 kg is initially at rest in the middle of the horizontal, frictionless surface of an ice-covered lake. Then a force directed east and with magnitude F(t)= (16.0 N/s )t is applied. Part A How far does the object travel in the first 6.00 s after the force is applied? Express your answer with the appropriate units. I got x=39.24 meters and i was sure that was correct, pleas help me understand why its...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT