Question

i dont want the answers just an explanation on how to do them please

1. Young millennials are viewed as the future of the restaurant industry. During 2011, this group consumed an average (i.e. mean) of 192 restaurant meals per person. Conduct a hypothesis test to determine if the last boom in the economy has caused an increase in the average annual frequency of consuming restaurant meals for this group. 1. (a) Establish the null and alternative hypotheses such that rejecting H.provides enough statistical evidence supporting the idea that the annual average meals per person (m) for this group has increased. Determine if this is a 2-tail, upper-tail, or lower-tail test. 2. (b) Enter the hypothesized value. 3. (c) To test the hypotheses, a randomly and independent sample of 150 millennials is selected. NPD marketing consulting firm found that the mean number of restau- rant meals consumed by this group in the sample taken was 201. Past data shows that the number of annual meals per person varies within the population with a variance of 3,025. Use the historical variation to determine this sample-to-sample variation of x 4. (d) What distribution do we need to use to solve this problem (t or z)? 5. (e) Use the results above to determine the test statistic. 6. (f) Calculate the p-value that corresponds to your test statistic. 7. (g) Find the critical value one would use if we want to minimize the probability of making a type 1 error to 0.04. 8. (h) Is there enough statistical evidence to reject the null, in favor of the alternative hypothesis? Choose the correct option. 1 .foot minute filers who mail

Answer 1

go for Solving this problem we can o normal distribution i.e. 2 becuse our population variance known and sumple size is also Ilgreeter than 30 iiic n 230. 62 is large ie. Test stellistic - 2= 7-es N NCoin) 62 = 3025 ão 201, . 6 955: ela 192, No 150.!.! - = 2.004. 2- 201 – 192 SS iso 9 4,4907 U & the For Prvalue & we have to calculate probability ie: Paralue= P [272.004] 120 = 0.02275Er 6 | since Prob (making Type I error] =a=0.04. is 203 20.05s 1.645 o r Table _ Value T from Mome Decision criteria Pubtably 6 from Pruelsea if Paralle <a we reject Ho ② from critical valle if Z arz we reject to Here Pavalue = 0.02275 Koiosa . we reject Ho 2x = 1.645 <2 =2.004 J at t=0.040 cases are reject Ho 1 In both Scanned with CamSpanner

let X: no. of meals per person in restaurant So we have to create the null and alternative hypothesis so Ho: el = 192 Nis Hei en 192 since. Ho: null hypothesis el is 192 is because this veleles is alredly given in a problem and Hii alterncelive hypothesis ie. e17192 ie our intrest because it's claim that average meal pesson cel is increased it must be greter than Hypothesized valuere. e1792. and Hi eing2 it's one teiled test it's on sight side we called it right teil Lor_ epper- tel. hypothesized value is ela192. © To test he selected sundom sample of size n=150. He found that mean number near of resterent nos consumeel by group is 2 = 201 sample mean se=12 201. and past data is giren e population Loariance is given thelt . 6-882" ie bes 2014 6 2 80 2 I : So f Scanned with CamScanner