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TWO 2.0 PC point charges are located on the x axis. One is at x=1.0 m, and the other is at x=-1.0m. What is the electric fiel

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Solution-The electric field on the y-axis at y = 0.50 m is E = 1.288 X 104 N/C.

The detailed solution is given below, please find the attached pages-

page no 1

page no 2

page no 3

unit -vector- Therefore, the net eletric field at y=0-5 m is given in E = Exh + Ey oût 1.288x10 • NC E = 1.28 x 104 N/C N/C/

thank you-


answered by: ANURANJAN SARSAM
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