Question

The owner of Bubba’s Barbeque is trying to determine a standard time for assembling each kind of sandwiches he sells. During a time study for assembling Bubba’s Famous Pulled Pork Sandwiches you recorded the following data in seconds.

Work Element	Cycles					Performance Rating
	1	2	3	4	5
Prepare hoagie roll, move to prep area, open roll.	31	26	33	34	31	105%
Get pork from smoker.	26	19	25	26	19	95%
Shred pork for sandwich	149	148	145	140	141	100%
Place pork on roll.	6	5	6	6	7	103%
Pour on special BBQ sauce.	10	12	11	12	10	110%
Close hoagie roll, slice in half.	15	17	16	18	14	105%
Wrap sandwich, place in pickup area.	20	19	21	22	18	108%

Allowances per 8-hour shift
Change into uniform	11 minutes
Unavoidable delays	3 minutes
Break	10 minutes
Lunch	25 minutes
Change out of uniform	11 minutes
Total	60 minutes

a.   Compute the normal time for each element (Nt). Based on that information, what is the job's NT.  (Round your answer to two decimals.)

b.   Compute the allowance factor (for the workday/time worked) based on the allowance information provided.   % (Round your answer to one decimal. Do not include the % sign on your answer.)

c.   Compute standard time for the job.   (Round your answer to two decimals.)

d.   If the owner expects demand for Bubba’s Famous Pulled Pork Sandwiches to be 105 per hour, how many employees should be assigned to prepare this kind of sandwich?  

Answer 1

a.

B C D E F 1 31 2 26 33 25 4 34 26 19 A 1 Work element 2 Prepare hoagie roll, move to prep area, open roll 3 Get pork from smoker. 4 Shred pork for sandwich 5 Place pork on roll. 6 Pour on special BBQ sauce. 7 Close hoagie roll, slice in half. 8 Wrap sandwich, place in pickup area. 140 5 Performance rating Average time Normal time 31 105% 31 32.55 19 95% 23 21.85 100% 144.6 144.6 103% 6 6.18 10 110% 11 12.1 14 105%' 16 16.8 18 20 21.6 10 15 12 17 19 11 16 21 12 18 22 2010 108%' 9 10 Total 255.68 11 12

Formula

b.

Allowance factor = (60/480)*100 = 12.5%

c.

Standard time = total normal time/(1-allowance factor)

=255.68/(1-12.5%) = 292.2057143 = 292.21 seconds (Rounded to 2 decimal places)

d.No of employees required = 105/(3600/292.2057143) = 8.522666667 = 9 (Rounded to nearest whole number)