Question

Consider the precious metal, gold (Au). It has the FCC structure and an atomic radius of 0.144 nm. It has an atomic mass of 52.00 g/mole and an atomic number 79. Avogadro's nmber is 6.023 x 10²³ atoms/mole.

Calculate the planar density for (111) plane (in atoms/nm²).

Hint: The area of an equilateral triangle is   $LaTeX: area=\frac{\sqrt[]{3}}{2}s^2$ a r e a = 3 2 s 2 where s is the length of the side of the triangle.

Answer 1

x EHI Solution - linear packing plane [1] is quien by PPF = Area of atoms on plane - plane LUR Number oq atoms on the plane [le] _ 318x) +(3xų) - 2 atoms the AB²+ Be AC² n +(art. CUR² n = P2R² h = 253R / Area of the plane a I (D) x (AB) - K (UR) x(23)R = UR² Therefore, . PPE a 2xlery - urra a 23 0.9069 Baratom . nm²