Question

sample of antimony pentachloride is sealed in a 100.0-cm glass bulb to which a pressure gauge is atached The buib is heued to 248 C and the gauge shows that the ressure in the bulb rises to 0.810 atm. At this temperature, the SbCls(g) is partally dissociated into Sbcy(e) and Cllg) according to the equation SbCly(g)SbCl()+C2(g) cal species in the At 248 °C, K,-1.07 for this reaction. Assume that the contents of the bulb are at equilibrium and calculate the partial pressure of the three di vessel. atm PsbCl

Answer 1

         SbCl5(g) -----------------> SbCl3(g)     + Cl2(g)

I           0.81                               0                     0

C          -x                                   +x                   +x

E         0.81-x                              +x                   +x

              Kp    = PSbCl3*PCl2/PSbCl5

              1.07   = x*x/(0.81-x)

              1.07*(0.81-x) = x^2

                   x    = 0.54

     PSbCl5    = 0.81-x    = 0.81-0.54 = 0.27atm

   PSbCl3      = x             = 0.54atm

   PCl2          = x               = 0.54atm