average arrival rate lambda = 10x60 =600 per hour
average service rate mu = 207 per hour
rho = 600/207 = 2.898
Probability that there is not customer in the system
P(0) = 1/ [ 1+rho+(rho)2/2 + (rho)3 xmu / 2 x( 3xmu-lambda)]
= 1/ [ 1+2.898+4.199+119.95] =0.0078
Lq = 0.0078 x lambda x mu x (rho)3 / 2 x ( 3xmu-lambda)2
= 0.0078 x600x207 x24.338 / 2 x 441
= 26.73
Waiting time in line Wq= Lq / lambda= 26.73 / 600 =0.04455 hours = 2.67 min.
Time in system = Wq +1/mu = 0.04455 +1/207 =0.04938 hours
= 2.962 min
Hence 3 persons can keep the time below 3 min,
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