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Solve the IVP and use the result to find amplitude and the phase shift (in degree). y +4 y = 0, y(0) = 1, y(0) = -2 Amplitu
A mass of 0.5 kg stretches a spring by 70 cm. The damping constant is c=2. External vibrations create a force of F(t) = 0.5 c
Question 3 Find the general solution of y+3y-2 y = 4e 47.given the particular solution y(t) = 2e, OA. y(t) = qel-3+v17)/2 +
TUULIUIT WIII save LISTES Question 4 Solve the given differential equation. X 16 + 25y=0 ©y=excı sin x+cz cosa Oy= ca sin x+
Question 5 10 points A3 kg object is attached to a spring and will stretch the spring 0.392 m. There is no damping in the sys
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Answer #1

+4y=0; y(0)=1, y(0)=-2 $+4=0 D=122 -.y = e, covat te sinat y (0)=1=c, y(o)=-2 = 24 4 =-1 1 2 TITIP TTTFTT ey= court - sinat

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