Question

For the compound ABC4 where A is hydrogen, B is a halogen and C is a chalcogen,

a) Indicate the total valence electrons

b) Draw a Lewis structure and any associated resonance structures. Other information, B is the least electronegative and can have an expanded octet.

c) From your structure, what is the molecular shape of each central element

d) Is your drawn structure polar or non polar

Answer 1

ABCU A = Hilton C=0 Valence Valence of Iodine B=1 yeast electronegative atom. of halogen faniely. FIIOU (al valence e- of Hydrogen = 1 7 6x 4 = 32 e of oxygen Total valence e-= 32+7+1 = 40 (6) Lewis structure - (i calculate ni = no of valence shell - of all atom & negative charge - positive Charge 40+0 -0 = 40 c) Calculerte marino.oy H atom x2) +mo. og atom other than Hydrogen x 8 - 1x2 + 5x8 (iii) Calculate na = 12-ni. 42-40=2. E = 1 vie. I can make only coradent bond. (in) cakulate nuan,-ng 40-2=38 no. of lone pair = 38 = 19 2 =u2 one no of bond OPY

To assign the structure ② find the central atom- either least in number or most electro positive here I is central atom it can expand its valency. Allocate the sworounding atom wow und central atom. ③ To fulfill octet of each atom utilise lone pair finally calculate formal charge. C) moleculare structure - of Hydrogen I= 7 valence e- & lvalence e- On - 2xy valency of oxygen lone pair. coordination no. of I is 5 so it have Trigonal planer structure but as oxygen is an chighly electronegative atom strongly an I will have squerre planer shape with your coordination number = 0 - so so it will bond with laty obrogen more o=1=0 co Ho oxygen attached to H will be beut.

(d) This compound is polar compound H stre to 1 8111 proton can caisley removed