Question

Part A The outstretched hands and arms of a figure skater preparing for a spin can be considered a slender rod pivoting about an axis through its center. (See the figure below (Figure 1).) When the skater's hands and arms are brought in and wrapped around his body to execute the spin, the hands and arms can be considered a thin-walled hollow cylinder. His hands and arms have a combined mass of 8.50 kg. When outstretched, they span 1.80 m; when wrapped, they form a cylinder of radius 25.0 cm The moment of inertia about the axis of rotation of the remainder of his body is constant and equal to 0.350 kg-m*. If the skater's original angular speed is 0.450 V/s, what is his final angular speed? EVO AED OB? Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Figure < 1 of 1 Provide Foedback Next >

Answer 1

IDENTIFY: Apply conservation of angular momentum to the motion of the skater. SET UP: For a thin-walled hollow cylinder 1 = mR?. For a slender rod rotating about an axis through its center, 1 = 1m12 EXECUTE: L = Le so 1;Q; = 1f0f

1; =0.350kg. m kg)(1.8 m2 = 2.645kg. m². If =0.350 kg. m2 + (8.50kg)(0.25 m= 0.881kg. m². 0f=1 545 kg m (0.45 rev/s) = 1.35 revis. If 0.88 kg.m )

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