Calculate the internal energy of one mole of helium
gas at a temperature of 280K. Assume ideal gas behavior.
U = n*c_v*T
c_v = R/(k - 1)
k is the adiabatic index, k=5/3 for Helium, because it is monatomic
U = n*R*T/(k - 1)
U = 1*8.314*280/(2/3)
U = 3491.88 J
Formula:
U = n*c_v*T
n is number of moles
c_v is the molar isochoric specific heat capacity
T is temperature in Kelvin
Formula for c_v:
c_v = R/(k - 1)
R is the universal gas constant
k is the adiabatic index, k=5/3 for Helium, because it is
monatomic
Thus:
U = n*R*T/(k - 1)
Data:
k:=5/3; R:=8.314 J/mole-K; n:= 1 mole; T:=280 K;
U= 1*8.314*280/(5/3-1)
Result:
U = 3491.88Joules
Calculate the internal energy of one mole of helium gas at a temperature of 280K. Assume...
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