Homework Answers
Monofluorination of methane is
H3C-H + F-F ------------> H3C-F + H-F
ΔHo = BDE of reactants - BDE of products [ BDE = Bond dissociation energy]
= BDE of [ H3C-H + F-F] - BDE [ H3C-F + H-F]
= 105 kcal/mol + 38 kcal/mol - [ 110 kcal/mol + 136 kcal/mol]
= -103 kcal/mol
Therefore,
ΔHo = -103 kcal/mol
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