Question

15. If you are amplifying a target sequence of 3.0 kb from a genomic DNA sample of size 3.0 x 10 kb, after 20 rounds of PCR what percentage of the total DNA would be your target sequence? 3.0-10 C. f= 220 X3.0 2 20 X3.0 B. f 220X3.0+3.0-1051.2% 2 30 =95.4% 104.9% A. f X3.0 3.0x10 16. The differences in the human genome between individuals are called B. genetic micro-satellites (GMS) D. minor allele frequency (MAF) A. single nucleotide polymorphisms (SNPS) C. genetic variation sites (GVS)
please explain

Answer 1

15 Sol: (A)

Here the target sequence is 3.0 kb and total number of cycles are 20, so the amplified product will be 2²⁰x3.0 and the total sample size is 3.0x10⁶. Therefore the amplified product 2²⁰x3.0 will be divided by the total size i,e 3.0x10⁶.

16. sol: (A) Single nucleotide polymorphisms (SNPs)