Question

The body temperatures of elephants are normally distributed with a mean of 97.7°F and a standard deviation of 0.83°F.

Step 1 of 4: What temperature would put a elephants in the 76th percentile? Include appropriate unit and round to 2 decimals.

Step 2 of 4: What temperature would put a elephants in the bottom 20% of temperatures? Include appropriate unit and round to 2 decimals.

Step 3 of 4: What is the probability that a elephants has a body temperature of 100°F or more?

Step 4 of 4: What is the probability that an elephants has a body temperature less than 98°F?

Answer 1

we have given :- Ma 977 6= 0.83 put a elephants Step D :-Temperature would in the 76th percentile." X = Temperahre [ka uf zo] (formula) zvalue. For foth percentile E 0.7] -f from table) * = 477 + 70.71 +0.83) E 48.28 ] step o temperature would put a elephants in the bottom 20 % of Temperatures [xe Mf 207 : z value for bottom 0.20 12= -0.84] = 97.7 760.84 +0.83) = 47.00

Step ® Probability for body temperature of 100° F or more pe x >100) » Cuse Normal Approximation). + P [ Moy > 100-937) PC 2) 2-77) -PC2<2-*] * 1-0.99+2 = 0.0028 stepe probability for body temperattre les man 98 - Pex (98) case. Normal App"). P[ 154 < 43-9482 = P(P<0.36] cuse 2 table) : : = 0.64067 0.83 J