A study of a population showed that males' body temperatures are approximately Normally distributed with a mean of 98.1 degrees and a population standard deviation of 0.50 degrees°F. What body temperature does a male have if he is at the 95th percentile? Draw a well-labeled sketch to support your answer.
He has a body temperature of....?
A study of a population showed that males' body temperatures are approximately Normally distributed with a...
Suppose the heights of women at a college are approximately Normally distributed with a mean of 64 inches and a population standard deviation of 1.5 inches. What height is at the 15th percentile? Include an appropriately labeled sketch of the Normal curve to support your answer.
Suppose the heights of women at a college are approximately Normally distributed with a mean of 66 inches and a population standard deviation of 1.5 inches. What height is at the 10th percentile? Include an appropriately labeled sketch of the Normal curve to support your answer.
. Body temperatures of adults are normally distributed with a mean of 98.60 degrees and a standard deviation of 0.73 degrees. a. What is the probability of a randomly selected adult having a body temperature less than 99.6 degrees or greater than 100.6 degrees? b. What is the probability of a randomly selected adult having a body temperature that differs from the population mean by less than 1 degree?
the body temperatures of adults are normally distributed with a mean of 98.6 degrees Fahrenheit and a standard deviation of 0.60 degrees Fahrenheit if 36 adults are randomly selected find the probability that their mean body temperature is greater than 98.4 degrees Fahrenheit
Body temperatures of adults are normally distributed with a mean of 98.60 degrees Fahrenheit and a standard deviation of 0.73 degrees Fahrenheit. Find the z- scores (round two decimal places) and the probability of a healthy adult having a body temperature between 98 to 99 degrees Fahrenheit (round four decimal places)?
Healthy people have body temperatures that are normally distributed with a mean of 98.20 degrees Fahrenheit and a standard deviation of 0.62 degrees Fahrenheit. If a healthy person is randomly selected, what is the probability that he or she has a temperature above 98.8 degrees Fahrenheit? A hospital wants to select a minimum temperature for requiring further medical tests. What should the temperature be, if we want only 2.5% of healthy people to exceed it?
The body temperatures of elephants are normally distributed with a mean of 97.7°F and a standard deviation of 0.83°F. Step 1 of 4: What temperature would put a elephants in the 76th percentile? Include appropriate unit and round to 2 decimals. Step 2 of 4: What temperature would put a elephants in the bottom 20% of temperatures? Include appropriate unit and round to 2 decimals. Step 3 of 4: What is the probability that a elephants has a body temperature...
In the 19th century, it was determined by experimentation that human body temperature is normally distributed N(98.6, 0.6) (in Fahrenheit F). Recently a new study has proposed that this should be modified to indicate that human body temperature is approximately normally distributed N(98.2,0.7) (F). a. Which of these two have a larger range of temperatures that represent 95% of the most common body temperatures? Provide an analysis that supports your conclusion. b. Over the course of 20 years an individual...
Body temperatures of adults are normally distributed with a mean of 98.60 °F and a standard deviation of 0.73 °F. What is the probability of a healthy adult having a body temperature between 97 °F and 99 °F?
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 97.1 99.3 99.9 99.5 97.5 96.4 99.1 96.6 99.4 98.7 97.6 98.1 Assume body temperatures of adults are normally distributed. Based on this data, find the 90% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 90% C.1. =