An airplane trip involves three legs with two stopovers. The first leg is due west for...
An airplane trip involves three legs with two stopovers. The first leg is due west for 620km; the second leg is 30o SE for 440km: and the third leg is at 53o SW for 550 km. The trip started at 3:15 PM and ended at 8:45 PM .
Find the Average velocity
Homework Answers
Here, D1 = - 620 i km
=> D2 = (440 * cos30 i - 400 * sin30 j) km
= (381.051 i - 200 j) km
=> D3 = (-550 * cos53 i - 550 * sin53 j) km
= ( - 331 i - 439.25 j) km
=> D = D1 + D2 + D3
= (- 569.95 i - 639.25 j) km
=> total displacement magnitude = 856.43 km
=> average velocity = 856.43/5.5
= 155.71 km/hr
=> direction = tan-1(639.25/569.95)
= 48.28 degree in SW direction .
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