a)
There are 4 kings in a standard 52-card deck.
The probability to choose first card as king = 4 / 52 = 1/13
If the sampling is done without replacement, now 3 kings remain in
51 cards.
The probability to choose second card as king = 3 / 51 = 1/17
The probability to choose first card as king and second card as
king if the sampling is done without replacement
= (1/13) * (1/17) = 0.005
b)
If the sampling is done with replacement, then 4 kings will
exist in 52 cards.
The probability to choose second card as king = 4 / 52 = 1/13
The probability to choose first card as king and second card as
king if the sampling is done without replacement
= (1/13) * (1/13) = 0.006
(a) What is the probability that the first card is a king and the second card...
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3. (5.4) Suppose that two cards are randomly selected from a standard 52-card deck. a) What is the probability that the first card is a king and the second card is a king if the sampling is done without replacement? b) What is the probability that the first card is a king and the second card is a king if the sampling is done with replacement? (With replacement means the card is put back into the deck after the first...
2).
a.b.
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