Homework Answers
Add Answer to:
2145° A 8. Find out the relationship of Vo and Vi in frequency domain. As frequency...
Design the second order band stop filter (notch filter) whose circuit is given below so that...
Design the second order band stop filter (notch
filter) whose circuit is given below so that the resonance
frequency is 400 Hz and Q = 5 and plot the change of the gain
according to the frequency in the Pspice program and show it on the
parameters of the filter. (Select LM741 for OPAMP.)
(values can be chosen randomly but it must be consistent
pspice is not required. R1 R2 Ra Rb what to choose.
Show that equations
C R₂...
53. A 2- order normalized Butterworth filter can be improved by using a so-called Chebeyshev filter...
53. A 2- order normalized Butterworth filter can be improved by using a so-called Chebeyshev filter The 3dBNLP second order NLP Chebeyshev transfer function is: 0.5012 2 +0.6449s+0.7079 Cheb3dBNLP(s) The Chebeyshev filter has some ripple in the passband but has better roll off, more attenuation in the stop band. If one can tolerate some ripple (sort of like a bouncy car ride) in the passband Chebeyshev filters typically have lower order than Butterworth filters. But, Butterworth filters have NO ripple...
Find the output voltage Vo as an expression in terms of the input sources Vi, v2,...
Find the output voltage Vo as an expression in terms of the input sources Vi, v2, v3, and the resistance R in the following op-amp circuit. 3. Ri Vy R: 4. In the following two stage op-amp circuit, find the output voltage Vo as an expression in terms of the input voltages v1, v2 and resistor values R1, R2, R3, and R4. R2 R ウー+
For each filter mentioned in the following cases, first simulate the circuit using Multisim. You can get a plot of the transfer function that is called the Bode plot. From the right toolbar, select &...
For each filter mentioned in the following cases, first simulate the circuit using Multisim. You can get a plot of the transfer function that is called the Bode plot. From the right toolbar, select "Bode Plotter". Change initial (I) and final (F frequencies to 1Hz and 200 KHz, respectively. Use a Voltage AC source as the input signal. You do not need to change any parameter from voltage AC source Connect "Bode Plotter" to input and output of your circuit...
The maximal single-peak ECG signal amplitude can be approximately 10 mV and the frequency range of...
The maximal single-peak ECG signal amplitude can be approximately 10 mV and the frequency range of ECG signal is usually between 0.5-200 Hz. Design a one-op-amp band-pass filter circuit that will amplify the ECG to have the maximal gain possible without exceeding the typical guaranteed linear output range (±10V) and will pass the range of frequencies indicated (Assume Ri = 10 kΩ).
250 mH Vi Given: The circuit shown above operates in steady state over a range of...
250 mH Vi Given: The circuit shown above operates in steady state over a range of frequencies. Vj is the input voltage and Vo is the output voltage. a. Determine the resistance value in K2 for which the half-power frequency, ??.s 10 krad/s. b. Using the value of R found in part a, determine the radian frequency (01 at which Vo lags V, by 40 c. Is this a High-pass or a Low-pass filter? Solution R= krad/s, and the filter...
3) BJT Gain Stage 1 mA BJT Parameters β 100 nVr-30 mV 5V Vo 6meg c,,-8 pF Vi 500 27u Vs VB is an ...
3) BJT Gain Stage 1 mA BJT Parameters β 100 nVr-30 mV 5V Vo 6meg c,,-8 pF Vi 500 27u Vs VB is an ideal dc voltage source a) What type of gain stage is realized by this BJT amplifier? b) Find a value for the input resistance Ri seen at node Vi. c) Find a value for the mid-band voltage gain Av-Vo/Vs. d) Determine the upper corner frequency fp2 imposed by the parasitic caps of the BJT
3) BJT...
Find The values, C1, C2, L1, L2, R1, R2, R3. The tweeter speaker can reproduce frequencies...
Find The values, C1, C2, L1, L2, R1, R2, R3. The tweeter speaker can reproduce frequencies greater than 6kHz, and the woofer can reproduce frequencies less than 200Hz. For proper sound, the midrange should reproduce all frequencies not produced by the subwoofer or tweeter. C2 C1 L2 V1 L1 R1 R3 R2 Midrange Tweeter Woofer Fig. 2. Equivalent model. The values of Ri, R2, R3, L1, L2, G. and C, are selected so that the filters have the same cutoff...
For the Multi Feedback Topology Band-pass Filter circuit shown in Figure 1 below, confirm the transfer...
For the Multi Feedback Topology Band-pass Filter circuit shown in Figure 1 below, confirm the transfer function H(s) given below 0 Figure 1: Multiple Feedback Topology Band-pass Filter (MFT BPF) Vo SR で 1 Ri R3 2R TR2C where the filter's parameters are o f: middle (center) frequency in Hz o Am: gain at middle frequency, fm, in V/V o B: bandwidth between half power frequencies in Hz o Q: quality factor. One of the nice features of this circuit...
LCR Circuit (Bandstop Filter) 1) Find differential equation for Vo (eliminate I’s) 2) Solve it fo...
LCR
Circuit (Bandstop Filter)
1) Find differential equation for Vo (eliminate I’s)
2) Solve it for Vo = Ao cos (ωt - ϕ)
*Using the same logic as shown on second image, please and
thank you!
I+ Ic IR Vi L. Find diftmil quation for Vo (elimnatc ll Is) Salve it for Vo Ao,cos (wt-f) band stop yo SOLVING FOR RLC band pass fiter acosuut)+ b sin (wt) Nott)AW sin (wt) + b Cos (ut) guess:-> Volt) 1-LCw2 I-LCW2
I+...
Design the second order band stop filter (notch
filter) whose circuit is given below so that the resonance
frequency is 400 Hz and Q = 5 and plot the change of the gain
according to the frequency in the Pspice program and show it on the
parameters of the filter. (Select LM741 for OPAMP.)
(values can be chosen randomly but it must be consistent
pspice is not required. R1 R2 Ra Rb what to choose.
Show that equations
C R₂...
53. A 2- order normalized Butterworth filter can be improved by using a so-called Chebeyshev filter The 3dBNLP second order NLP Chebeyshev transfer function is: 0.5012 2 +0.6449s+0.7079 Cheb3dBNLP(s) The Chebeyshev filter has some ripple in the passband but has better roll off, more attenuation in the stop band. If one can tolerate some ripple (sort of like a bouncy car ride) in the passband Chebeyshev filters typically have lower order than Butterworth filters. But, Butterworth filters have NO ripple...
Find the output voltage Vo as an expression in terms of the input sources Vi, v2, v3, and the resistance R in the following op-amp circuit. 3. Ri Vy R: 4. In the following two stage op-amp circuit, find the output voltage Vo as an expression in terms of the input voltages v1, v2 and resistor values R1, R2, R3, and R4. R2 R ウー+
For each filter mentioned in the following cases, first simulate the circuit using Multisim. You can get a plot of the transfer function that is called the Bode plot. From the right toolbar, select "Bode Plotter". Change initial (I) and final (F frequencies to 1Hz and 200 KHz, respectively. Use a Voltage AC source as the input signal. You do not need to change any parameter from voltage AC source Connect "Bode Plotter" to input and output of your circuit...
250 mH Vi Given: The circuit shown above operates in steady state over a range of frequencies. Vj is the input voltage and Vo is the output voltage. a. Determine the resistance value in K2 for which the half-power frequency, ??.s 10 krad/s. b. Using the value of R found in part a, determine the radian frequency (01 at which Vo lags V, by 40 c. Is this a High-pass or a Low-pass filter? Solution R= krad/s, and the filter...
3) BJT Gain Stage 1 mA BJT Parameters β 100 nVr-30 mV 5V Vo 6meg c,,-8 pF Vi 500 27u Vs VB is an ideal dc voltage source a) What type of gain stage is realized by this BJT amplifier? b) Find a value for the input resistance Ri seen at node Vi. c) Find a value for the mid-band voltage gain Av-Vo/Vs. d) Determine the upper corner frequency fp2 imposed by the parasitic caps of the BJT
3) BJT...
Find The values, C1, C2, L1, L2, R1, R2, R3. The tweeter speaker can reproduce frequencies greater than 6kHz, and the woofer can reproduce frequencies less than 200Hz. For proper sound, the midrange should reproduce all frequencies not produced by the subwoofer or tweeter. C2 C1 L2 V1 L1 R1 R3 R2 Midrange Tweeter Woofer Fig. 2. Equivalent model. The values of Ri, R2, R3, L1, L2, G. and C, are selected so that the filters have the same cutoff...
For the Multi Feedback Topology Band-pass Filter circuit shown in Figure 1 below, confirm the transfer function H(s) given below 0 Figure 1: Multiple Feedback Topology Band-pass Filter (MFT BPF) Vo SR で 1 Ri R3 2R TR2C where the filter's parameters are o f: middle (center) frequency in Hz o Am: gain at middle frequency, fm, in V/V o B: bandwidth between half power frequencies in Hz o Q: quality factor. One of the nice features of this circuit...
LCR
Circuit (Bandstop Filter)
1) Find differential equation for Vo (eliminate I’s)
2) Solve it for Vo = Ao cos (ωt - ϕ)
*Using the same logic as shown on second image, please and
thank you!
I+ Ic IR Vi L. Find diftmil quation for Vo (elimnatc ll Is) Salve it for Vo Ao,cos (wt-f) band stop yo SOLVING FOR RLC band pass fiter acosuut)+ b sin (wt) Nott)AW sin (wt) + b Cos (ut) guess:-> Volt) 1-LCw2 I-LCW2
I+...
Most questions answered within 3 hours.
-
20.
A diamond mine is expected to produce regular annual cash flows
of $1 million for...
asked 1 minute from now -
Within the client’s IT system, supplier information is contained
in a supplier master file (SMF). Each...
asked 1 minute from now -
Explain why sound travels faster in warm air than in cool air.
Suppose the room temperature...
asked 4 minutes ago -
The measured glucose level one hour after having a sugary drink
varies according to the normal...
asked 11 minutes ago -
Mic2 is a gene present on both the X and Y chromosome
of humans. Suppose a...
asked 10 minutes ago -
Consider this balanced chemical equation:
H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)
In the first 10.0 seconds of the reaction, the concentration...
asked 13 minutes ago -
A neuropathologist is using a device with a thin circular coil
of current-carrying wire of radius...
asked 17 minutes ago -
A Carnot engine whose low-temperature reservoir is at 18.0°C has
an efficiency of 21.9%. By how...
asked 20 minutes ago -
A carpenter is making doors that are 2058.0 millimeters tall. If
the doors are too long...
asked 20 minutes ago -
Suppose you are analyzing a competitor of Levi's Luxury Shop and
determine that Current Assets are...
asked 33 minutes ago -
statistics show
that 40% of adults sleep with socks. Eight adults are randomly
selected
what is...
asked 41 minutes ago -
In
a blast furnace, coke, which is solid carbon, reacts with O2(g) to
form carbon monoxide....
asked 48 minutes ago