Balanced equation:
2 Al(s) + 6 HCl ====> 2 AlCl3(aq) + 3 H2(g)
Reaction type: single replacement
2.9 gm of Aluminum = 2.9 /26.98 = 0.10748 Moles
0.10748 Moles of Aluminum will produce 0.1612 Moles (0.10748 x 3/2) of hydrogen
We can find the volume of Hydrgen gas at STP using ideal gas equation
PV = nRT
where P is the absolute pressure, V is the volume of gas , n is the amount of gas (SI unit moles),, and T is the Temperature .
1 x V = 0.1612 x 0.0821 x 273
V = 3.61 L
Volume of Hydrogen gas 3.61 Liter
Balanced equation:
2 Al(s) + 6 HCl ====> 2 AlCl3(aq) + 3
H2(g)
Reaction type: single replacement
2.9 gm of Aluminum = 2.9 /26.98 = 0.10748 Moles
0.10748 Moles of Aluminum will produce 0.1612 Moles (0.10748 x 3/2) of hydrogen
We can find the volume of Hydrgen gas at STP using ideal gas equation
PV = nRT
where P is the absolute pressure, V is the volume of gas , n is the amount of gas (SI unit moles),, and T is the Temperature .
1 x V = 0.1612 x 0.0821 x 273
V = 3.61 L
Volume of Hydrogen gas 3.61 Liter
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