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Find the equations of the tangents to the curve x = 922 + 9, y = 6+ + 3 that pass through the point (18,9). (smaller slope) y = ya (larger slope)
Find the equations of the tangents to the curve x = 922 + 9, y = 6+ + 3 that pass through the point (18,9).
Please explain, thank you. Show that the curve x = 5 cos t, y = 2 sin tcos t has two tangents at (0, 0) and find their equations (smaller slope) (larger slope) Show that the curve x = 5 cos t, y = 2 sin tcos t has two tangents at (0, 0) and find their equations (smaller slope) (larger slope)
Find the equation of the tangents to the curve y = sin x at x = -1, 0, and Graph the curve over the interval together with their tangents. Label each curve and tangent What is the equation of the tangent (I) to the curve at x = -x? y= What is the equation of the tangent (II) to the curve at x = 0? y=0 What is the equation of the tangent (Ill) to the curve y= Choose the...
Find the tangent equation to the given curve that passes through the point (18,9). Note that due to the t2 in the x equation and the t3 in the y equation, the equation in the parameter t has more than one solution. This means that there is a second tangent equation to the given curve that passes through a different point. x = 9t2 + 9 y = 6t3 + 3
(a) Find the slope m of the tangent to the curve y = 2 + 4x2 − 2x3 at the point where x = a. m = (b) Find equations of the tangent lines at the points (1, 4) and (2, 2). y(x) = (at the point (1, 4)) y(x) = (at the point (2, 2)) (c) Graph the curve and both tangents on a common screen. say and the sose m of the target to the survey * 2...
Problem 3 (12 points) The curve with parametric equations (1 + 2 sin(9) cos(9), y-(1 + 2 sin(θ)) sin(0) is called a limacon and is shown in the figure below. -1 1. Find the point (x,y 2. Find the slope of the line that is tangent to the graph at θ-π/2. 3. Find the slope of the line that is tangent to the graph at (,y)-(1,0) ) that corresponds to θ-π/2. Problem 3 (12 points) The curve with parametric equations...
16. Find the number of tangents to the curve y=-* passing through P = (1, 2).
Find the tangent equation to the given curve that passes through the point (4, 3). Note that due to the t2 in the x equation and the 3 in the y equation, the equation in the parameter t has more than one solution. This means that there is a second tangent equation to the given curve that passes through a different point. x = 3t2+1 y = 2t3 + 1 y = (tangent at smaller t) y = (tangent at larger t)
The curve shown below is called a Bowditch curve or Lissajous figure. Find the point in the interior of the first to the curve is horizontal, and ind the equations of the two tangents at the origin. What is the point in the interior of the frst quadrant where the tangent to the curve is horizonta? an ordered pair. Type an exact answer, using radicals as needed ) What is the equation of the tangent at the origin when t...
(a) Find the slope of the curve y = x - 8x at the given point P(2. - 8) by finding the limiting value of the slope of the secants through P. (b) Find an equation of the tangent line to the curve at P(2.-8). (a) The slope of the curve at P(2. - 8) is
The slope at each point (x, y) on a curve y = f(x) is given by 1 f'x)= V4x(4v-1) If the curve goes through the point (16,0), find f(x) f(x) Tries 0/10 Submit Answer The slope at each point (x, y) on a curve y = f(x) is given by 1 f'x)= V4x(4v-1) If the curve goes through the point (16,0), find f(x) f(x) Tries 0/10 Submit Answer