Question

along the top, but not along the bottom edge. The leg of the weld has a width of in (the maximum possible). The dimensions are l1 = 6 in and a = 4 in. In solving this problem be sure to carefully consult Table 9-1. Be sure to include both primary and secondary shear stresses. 2. (a) Identify the location in the weld metal of the worst throat stress, and find the magnitude of this stress. Since there is no symmetry here, you should check both ends of the weld pattern. (b) Use table 9-4 from the text to find the allowable shear stress. In using this table use values from the weaker of the two parent metals for checking the strength in the leg of the weld. Assume an E70xx electrode for checking the strength of the throat of the weld. Note that the strengths of A36 are given in the text of example 9-3 in your text, p. 485. State whether the proposed weld satisfies AISC code. (c) Determine the worst stress if everything is exactly the same, except that the vertical leg of the L-shaped weld pattern now runs down the right edge of the column rather than down the left edge of the bracket. Does this arrangement satisfy code? (d) Why is it somewhat questionable to apply our line weld analysis techniques in this particular problem?

Answer 1

44 kip xc " P. Z =P Primary shear stress, А (214-a) +334 Secondary shear stress, LA) G = Mr J ८ = 3000x exto I 3txt + 2 21d,-a)t + 3t xe l-a) +1.5t 2(4-a) + 3 hors + 1-5 2 بز

J = 3 3 Id-a)/3² + (-a) ²) + 12 6 J = 2.25 + 1l 1 bode-alfle-a) + 27% 6 put it in (A) Ez = 3000 e xde²+2.25 1-afb1.-23+27 22-5 + 6 Add to the Eyes & equate it to shear strength of welding material. Tall. = 1 + Z₂. from this, we can calculate weld size.

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