Question

..sliding down a grass hill on a piece of cardboard was a fun summer activity! There was a hill near a park in south St. Louis that had an incline of something like 30 degrees. Once I got started on the top of the hill, I could ride for a distance on the order of 50 meters before arrived at the bottom of the hill. At that time, my mass was just a puny 50 kg. This quiz deals with my acceleration down the hill. You may assume the coefficient of kinetic friction, Ak=0.4. PART 1: (1 point) Draw a diagram of the physics of the problem (similar to what you see in the physics book and lecture charts - showing all the forces involved) , using a generic angle, e for the inclination of the hill, and a generic mass, m, for the mass of the rider Develop the equation for the acceleration +sled. When you develop this equation, explain any new variables that you might use in your formulation. Remember to consider units (they are your friend!). PART 2: (1 point) and m, and determine the specific value of Use the specific values in the problem statement for Professor Pearson's acceleration when he was a kid. PART 3: (no extra points) For no extra credit, but for generating self-esteem and a bow/tip-of-the-hat from Professor Pearson, what was his speed at the end of the ride down the hill if he started with no speed at the beginning? Would you consider that fast or slow? Can you compare it to something else as a reference such as bicycle speed or a car speed or a marathon runner?

university physics please show your work

Answer 1

Answer 2

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Nnormal reaction fr - friebional force = UN »N Ne malosco mocos F= ma Since a = Fnet - F- for = mg sino - mgloso.se E-ma so ja = gsino - Mg loso] 2) 0-30°, m = al sokg So a = 9.8x Sin 30 – 0.489.8x Cos 30 = 151 m/s? 3) By consonation of energy PE; = kEgt heat lost righ - 1 mv. } + foxd wigh - Ini dig + Juning losed Vg² - agh- ag coso jud Sino = h so h = 50x0 - Jag (h- judoso) Vf - 12.26 m/s Scanned with CamScanner AM