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Calculate either H,0) or (OH) for each of the solutions. Solution A: OH) = 2.11 x 10 PM Solution A: H,0) = Solution B: (OH)
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Solution A [on] = 2011x107 m 0.473x10 that kwa [117] [OH-] = 1x 1014 We know 1x1014 - 1x1014 1 X 10 2011 x 101 (4+] = [or I

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