Question

The enzyme xylose isomerase is used industrially for the conversion of the sugar glucose to fructose as depicted by the following reaction scheme and generic rate law:

glucose ➞ fructose rate = k [glucose]n

For one reaction with a high amount of enzyme present, the concentration of fructose is monitored over the course of a reaction.

Time(minutes)	[fructose](mol/L)
0.0	0.00
3.9	0.52
7.2	0.95
18.8	2.49
23.5	3.11

What is the order of reaction?

A. Zeroth order (n = 0)

B. First order (n = 1)

C. Second order (n = 2)

D. More information is needed to determine the order.

Please Explain how you found your answer.

Answer 1

The reaction is as follows glucose-fructose The concentration of fructose with time is as follows Time minutes (mol/min fructose 0 3.9 7.2 18.8 23.5 0 0.52 0.95 2.49 3.11 The rate of the reaction is given as r- k[glucose] n is the order of the reaction. If the order of the reaction is 0, the rate of the reaction is as follows k [glucose] Thus, the rate of the reaction for a zeroth order reaction is constant. If the order of the reaction is 1, the rate of the reaction is as follows r ] Thus, the rate of the reaction for a first order reaction is not constant If the order of the reaction is 2, the rate of the reaction is as follows KI glucose KI glucose Thus, the rate of the reaction for a second order reaction is not constant.

The rate of the reaction is calculated as the ratio of change of concentration of products to the change in the time Д| fructose At Calculate the rate of the reaction at different times ΔΙ fructose At 0.52-0.00mol 0.39-0.00 Lmin mol = 0.13 min The rate of reaction for second interval is ΔΙ fructose At 0.95-0.52moi 7.2-3.9 JLmin min The rate of reaction for third interval 1s ΔΙ fructose 1' E At 2.49-0.95mol 18.8-72Lmin min The rate of reaction for fourth interval 1s Δ| fructose At 3.11-2.49 mol 23.5-18.8 Lmin 0.13720 min

The rate of the reaction is same for all the time intervals, which is 0.13. Thus, the rate of the reaction is a constant. Since the rate of the reaction is a constant, the reaction is of 0 order The correct option is option A